Index exceeds matrix dimensions.AGAIN
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FAILED AGAIN ;-(((( Accepted wrong one
dU(35)=55;
f = figure('Position',[10 10 600 600]);
dat = {-1,1,1;0,-1,0;0,0,-1;1,0,0};
cnames = {'18','29','51'};
rnames = {'12','26','35','44'};
t = uitable('Parent',f,'Data',dat,'ColumnName',cnames,...
'RowName',rnames,'Position',[10 10 590 590]);
blnA = logical( A == -1 );
blnOut = find(any(A == -1,2));
maxValue = max(negcolumn)
index = rnames{maxValue}
dU(tzan)
maxValue =
3
index =
35
Index exceeds matrix dimensions.
Please give me easy way...
Help, Help, Help It is my last question?
6 个评论
Light
2013-6-8
Image Analyst
2013-6-8
编辑：Image Analyst
2013-6-8
Please stop posting the question over and over again. Learn how to use the debugger: http://blogs.mathworks.com/videos/2012/07/03/debugging-in-matlab/. It will solve all your problems. It really will. We can't help you because we don't know what A is. Put a "clear all" at the beginning of your code and get rid of that pre-existing A. You will find your code crashes when it tries to access A. Then proceed to fix your code using the debugger.
Light
2013-6-8
Image Analyst
2013-6-8
No one even knows what you want to do. The code is so bad that we can't even figure it out. Please explain, in words, what you want to do with the cnames and rnames and the table. It seems like you're looking for -1's but I don't know what you want to do if you find them.
Azzi Abdelmalek
2013-6-8
Light, can you enlighten us by making your question breve and clear, or maybe you need to learn basics of Matlab
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