I want this for loop to dispaly the smallest calculated value of PE. What would be the best way of going about this?

Question

Brad Holder 2021-3-28

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/786151-i-want-this-for-loop-to-dispaly-the-smallest-calculated-value-of-pe-what-would-be-the-best-way-of-g

回答： Jeff Miller 2021-3-28

for t1 = 0:1:90,t2 = 0:1:90;  
        t1;
        t2;
        h1 = -b1*cosd(t1);
        h2 = -(b1*cosd(t1)+b2*cosd(t2));
        d1 = sqrt((x1-a1*sind(t1)).^2 + (y1+a1*cosd(t1)).^2)-L1;
        d2 = sqrt((x1-(b1*sind(t1)+a2*sind(t2))).^2+(y2+(b1*cosd(t1)+a1*cosd(t2))).^2)-L2;
        PE = (1/2)*k1*d1.^2 + w1*h1 - f1*b1*sind(t1) + (1/2)*k2*d2.^2 + w2*h2 - f2*(b1*sind(t1)+b2*sind(t2));
        
        if PE == min
            disp PE
        end
end

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Answer 1

Jeff Miller 2021-3-28

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https://ww2.mathworks.cn/matlabcentral/answers/786151-i-want-this-for-loop-to-dispaly-the-smallest-calculated-value-of-pe-what-would-be-the-best-way-of-g#answer_660816

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% something like this:
minPE = realmax;
for t1 = 0:1:90,t2 = 0:1:90;  
        t1;
        t2;
        h1 = -b1*cosd(t1);
        h2 = -(b1*cosd(t1)+b2*cosd(t2));
        d1 = sqrt((x1-a1*sind(t1)).^2 + (y1+a1*cosd(t1)).^2)-L1;
        d2 = sqrt((x1-(b1*sind(t1)+a2*sind(t2))).^2+(y2+(b1*cosd(t1)+a1*cosd(t2))).^2)-L2;
        PE = (1/2)*k1*d1.^2 + w1*h1 - f1*b1*sind(t1) + (1/2)*k2*d2.^2 + w2*h2 - f2*(b1*sind(t1)+b2*sind(t2));
    if PE < minPE
       minPE = PE;
    end
end
disp minPE