Reshape a cell avoiding the loop

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Giorgos Papakonstantinou 2013-6-11

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I have the cell for example:

a = 
      '0.0'    '0.0' 
      '0.1'    '-0.4'
      '0.1'    '0.8' 
      '0.2'    '2.3' 
      '0.3'    '3.4' 
      '0.3'    '-3.2'
      '0.4'    '-6.9'
      '0.5'    '-1.8'
      '0.5'    '7.2' 
      '0.6'    '10.0'

and I want o reshape it like this.

d = 
      '0.0'    '0.0'     '0.3'    '-3.2'
      '0.1'    '-0.4'    '0.4'    '-6.9'
      '0.1'    '0.8'     '0.5'    '-1.8'
      '0.2'    '2.3'     '0.5'    '7.2' 
      '0.3'    '3.4'     '0.6'    '10.0'

I want to avoid the loop because the cell dimensions are very large. Thank you!

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Answer 1

Iain 2013-6-11

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I think:

 b = a';
 c = reshape(b,cols,rows,numel(a)/cols/rows);
 c = permute(c,[2 1 3]);
 d = reshape(c,[],rows);

should do it...

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Giorgos Papakonstantinou 2013-6-11

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I think by accident you made a typo.

It should be:

reshape(c,2,[])

Thank you. I really don't understand how permute works.

Iain 2013-6-11

Permute swaps dimensions round.

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Answer 2

the cyclist 2013-6-11

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编辑：the cyclist 2013-6-11

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d = [a(1:5,:),a(6:10,:)];

You can generalize this, of course, but you did not provide enough detail. If you always want the top half and bottom half, for example, you could use the size() command to determine the "height", and use half the height to determine the cutoff, which I just hard-coded as 5 here.

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Giorgos Papakonstantinou 2013-6-11

What if the the initial cell a has 100 rows and two columns (size 100x2). How do I cut the cell in sets of 5 avoiding the for loop. The resulting cell will have size 5x40 and it will start just as the cell d that I indicated above.

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Answer 3

Giorgos Papakonstantinou 2013-6-11

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I am sorry I should be more explanatory. Let's say that I want to split in sets of 2 and concatenate them.

so it would be:

c =

    '0.0'    '0.0'     '0.1'    '0.8'    '0.3'    '3.4'     '0.4'    '-6.9'    '0.5'    '7.2' 
    '0.1'    '-0.4'    '0.2'    '2.3'    '0.3'    '-3.2'    '0.5'    '-1.8'    '0.6'    '10.0'