How to adjust counters for multiple for loops

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Kaylee Cornish
Kaylee Cornish 2021-4-2
回答： William Rose 2021-4-2
I'm trying to create two seperate arrays using different for loops:
for k=1:2*layers
for j=2:2*layers+1
ztop(k)=pt*(layers-(k-1));
zbot(j)=pt*(layers-(j-1));
end
end
Essentially I want counter k to be from 1 to 2 times the layers and counter j to be from 2 to 2 times the layers plus one.The j array keeps entering as a 1x5 instead of 4. How can I fix this?
  1 个评论
DGM
DGM 2021-4-2
Your problem description is ambiguous. I don't know what your code is trying to do conceptually. I know you tried to explain the indexing you're looking for, but sometimes conversational language is more ambiguous than we'd like to admit.
Let's start with what you've got already. I'm going to assume some value for layers:
layers=5;
k=1:2*layers
j=2:2*layers+1
This gives us:
k =
1 2 3 4 5 6 7 8 9 10
j =
2 3 4 5 6 7 8 9 10 11
In terms of endpoints or spacing, how do these vectors differ from what you're trying to achieve?

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回答（2 个）

Steven Lord
Steven Lord 2021-4-2
Ran in:
Compare:
layers = 5;
x1 = 2:2*layers+1
x1 = 1×10
2 3 4 5 6 7 8 9 10 11
x2 = (2:2*layers)+1
x2 = 1×9
3 4 5 6 7 8 9 10 11
The operator precedence matters. The colon operator : is at level 7, right after the plus operator + at level 6.
x1 computes (2*layers+1) and uses it as the second input to colon.
x2 creates the array using colon then adds 1 to each element.
William Rose
William Rose 2021-4-2
@Kaylee Cornish,
You can use two non-nested for loops.
The second foor loop fills up the vector zbot.
zbot will be 1x4.
layers=2;
pt=1;
for k=1:2*layers
ztop(k)=pt*(layers-(k-1));
end
for j=2:2*layers+1
zbot(j-1)=pt*(layers-(j-1));
end
Then you just have to remember later that zbot(1) goes with j=2, zbot(4) goes with j=5, etc.

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