How can I fix this error?

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Hazal Yuvgun
Hazal Yuvgun 2021-4-7
评论： Hazal Yuvgun 2021-4-7
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Hazal Yuvgun
Hazal Yuvgun 2021-4-7
I want to extract the first row from others

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采纳的回答

Khalid Mahmood
Khalid Mahmood 2021-4-7
编辑：Khalid Mahmood 2021-4-7
function y=Question5(x)
y=[];
rows=size(x,1);
y(1,:)=x(1,:);
for i=2:rows
y(i,:)=x(i,:)-x(1,:);
end
end
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Khalid Mahmood
Khalid Mahmood 2021-4-7
编辑：Khalid Mahmood 2021-4-7
in for loop y(i) ensures all rows. Like y(i,:)=x(i,:)-x(1,:); This is working now

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更多回答（2 个）

Steven Lord
Steven Lord 2021-4-7
Where in your code do you define a variable named i? If the answer is some form of "nowhere" or "I don't" then MATLAB will call the built-in function to determine the value that should be used. That built-in function returns neither a positive integer value nor a logical value.
Khalid Mahmood
Khalid Mahmood 2021-4-7
function y=Question5(x,i)
y=[];
if i==1
y=x(1,:);
else
y=x(i,:)-x(1,:);
end
end
  1 个评论
Khalid Mahmood
Khalid Mahmood 2021-4-7
save above code as Question5.m file. Then
>>x=randi([-10 10],5,3); % define x, or whatever x you want
>>y=Question5(x,1)
>>y=Question5(x,2)
>>y=Question5(x,3)
But I think you may need following code for advanced logic.

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