when I put a one variable, a function says A, but when I put a variable on row it says B

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AhyounLee
AhyounLee 2021-4-11
编辑： Shadaab Siddiqie 2021-4-14
I made a function to make radian to degree.
And the result have to -180<(degree)<180. So 'r2d' is works well.
but If I put the syntax like " radian = [-5/2*pi:pi/5:5/2*pi] " to function on script, it dosent work well.
How can fix them?
script is :
clear, clc
%임의의 radian을 degree로
radian = [-5/2*pi:pi/5:5/2*pi] ;
degree = r2d(radian) ;
r_d = [radian; degree]'
function r2d is :
function R = r2d(x)
% radian을 degree로 변환
f = x./pi ;
R = f.*180 ;
% radian이 pi 초과인 경우
if f>1
cost = fix(f) ;
R = 180 .* (f - fix(f)) ;
if R == 0
R = 180
end
% radian이 -pi 미만인 경우
elseif f<-1
cost = fix(f) ;
R = 180 .* (f - fix(f)) ;
if R == 0
R = -180
end
% pi가 -pi 이상 pi 이하일 경우
else
end

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回答（1 个）

Shadaab Siddiqie
Shadaab Siddiqie 2021-4-14
编辑：Shadaab Siddiqie 2021-4-14
From my understanding you want to convert radians to degree such that result is in the range [-180,180]. It is unclear if your r2d(0) should output 0 or -180. But here is a solution which might help you.
function degrees = Untitled2(varargin)
radang = cell2mat(varargin);
if nargin < 1
error('Invalid number of inputs');
end
if ischar(radang)
error('Input must be a angle or a vector of angles')
end
degreesNotInRange = rem(360+radang*180/pi,360);
degrees = rem(degreesNotInRange,360)-180;
You can run it
>> r2d(pi,pi/6,pi/4,pi/2,2*pi/3)
>> r2d(1.48)
>> r2d(0:pi/6:pi)

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