Error using randi Size inputs must be scalar (Matlab)
显示 更早的评论
I have entries parameters A and B, and I have to obtain C with for loop, where C is the random subset of B of size Ai
I program this
for i=1:n
C=randi([0,1],B,A(i));
end
But I get the error (Error using randi ==> inputs must be scalar)
How can I fixe the problem
1 个评论
Rik
2021-4-12
How are you making sure B and A(i) are positive scalars?
采纳的回答
"C is the random subset of B of size Ai" :
for i = 1:n
% Without repetitions:
C = B(randperm(numel(B), A(i)));
% Or with repetitions:
C = B(randi([1, numel(B)], 1, A(i)));
... use C now
end
5 个评论
high speed
2021-4-12
Rik
2021-4-12
If you have an array with these values:
B=[3 6 9];
Now you can take random samples in two ways:
C=[6 3 6]
%or
C=[6 9 3]
%or
C=[3 3 3]
%or
...
Or like this:
C=[3 6]
%or
C=[3 9]
%or
C=[9 6]
Jan
2021-4-13
@high speed: Simply try it:
B = 1:4;
% No repetitions:
C = B(randperm(numel(B), 4))
C = B(randperm(numel(B), 4))
C = B(randperm(numel(B), 4))
C = B(randperm(numel(B), 4))
% With repetitions:
C = B(randi([1, numel(B)], 1, 4));
C = B(randi([1, numel(B)], 1, 4));
C = B(randi([1, numel(B)], 1, 4));
C = B(randi([1, numel(B)], 1, 4));
Do you see it? With repetitions the values in the output can repeat. Then C can be longer than B. Without repetition, C is a permutation of the elements of B.
high speed
2021-4-13
Jan
2021-4-13
@high speed: Sorry, what? Yes, in my example, I've used 4 to clarify what "repetition" means. You have asked for this detail. But the code in my answer does contain A(i).
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