Selecting element at same position in a matrix

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Joel Schelander 2021-4-13

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评论： Joel Schelander 2021-4-13

VID1 is a 3x3 cell. I choose a value randomly from the cell like thus.

ID1=VID1{ randi([1,size(VID1,1)],1), randi([1,size(VID1,2)],1 )};

If I have randomly chosen element VID{1,1}. I want to choose an element in the same position in another cell Vehicle1 (3x3 cell). How can I do this?

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Answer 1

Jan 2021-4-13

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编辑：Jan 2021-4-13

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If you need the indices again, store them in variables:

i1 = randi([1, size(VID1, 1)]);
i2 = randi([1, size(VID1, 2)]);
ID1 = VID1{i1, i2};
V1  = Vehicle1{i1, i2};

It might be easier to use linear indices:

index = randi([1, numel(VID1)]);
ID1 = VID1{index};
V1  = Vehicle1{index};

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Joel Schelander 2021-4-13

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Hi @Jan thank you, that helps! However now I get different values compared to my previous method. Was my previous method wrongly stated? I thought the result INCREASE2 (I later save INCREASE2 in a cell) should contain the same values as before.

Just asking if you can see something obvious

Before:

    for jj=1:numel(VID1)
        V11=Vehicle1{jj};
        ID1=VID1{jj};
        for jj2=1:numel(VID2)
           
           V22=Vehicle2{jj2};
           ID2=VID2{jj2};
%Removes all doubles   
if numel(intersect(ID1,ID2))
continue
end
            INCREASE2{jj,jj2}=max(HH2+V11+V22)./max(HH2);
           IDcell2{jj,jj2}=[ID1 0 ID2];
        
        end
    end
    

After:

    for o=1:numel(INCREASE2)
   
    for oz=1:999
k1 = randi([1, size(VID1, 1)]);
kk1 = randi([1, size(VID1, 2)]);
ID1 = VID1{k1, kk1};
V1  = Vehicle1{k1, kk1};
k2 = randi([1, size(VID2, 1)]);
kk2 = randi([1, size(VID2, 2)]);
ID2 = VID2{k2, kk2};
V2  = Vehicle1{k2, kk2};
      if numel(intersect(ID1,ID2))
 continue
      else
          IDCELL{o}={ID1; ID2};
          INCREASE2{o}=max(HH2+V1+V2)./max(HH2);
          break
      end
    end
    
end