Splitting an array?
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Hello everybody. Here is the issue.. having the array C{1,1} I normally don’t know the exact number of rows. How can I split that matrix in 2 parts?, I can use :
o = (C{1,1}(:,[1:end/2]));
to split the first part, however the second part is not that easy because the number of rows varies at the interior in each ‘C’ array. Thank you.
采纳的回答
Data = C{1,1};
Len = size(Data, 2);
Half = floor(Len / 2);
Part1 = Data(:, 1:Half);
Part2 = Data(:, Half+1:Len);
It is not clear to me, what this means: "second part is not that easy because the number of rows varies at the interior in each ‘C’ array"
By the way, 1:x is a vector already. The square brackets are Matlab concatenation operator. [1:x] concatenates 1:x with nothing and is a waste of time in consequence.
6 个评论
Fercho_Sala
2021-4-24
Fercho_Sala
2021-4-24
Jan
2021-4-25
Yes, a loop will solve this:
C1 = cell(size(C));
C2 = cell(size(C));
for k = 1:numel(C)
Data = C{1, k};
Len = size(Data, 2);
Half = floor(Len / 2);
C1{k} = Data(:, 1:Half);
C2{k} = Data(:, Half+1:Len);
end
Fercho_Sala
2021-4-26
Fercho_Sala
2021-4-26
编辑：Fercho_Sala
2021-4-26
Fercho_Sala
2021-4-26
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