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Counting the number of runs in a sequence

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olig
olig 2013-7-8
I have a sequence made up a number of 1's and 0's and I want to count how many runs of numbers occur within the sequence. For example taken the matrix
A=[1,1,1,0,0,1,1,1,1,0,0,0,0,1]
The 1st run: 1,1,1 The 2nd run: 0,0 The 3rd run: 1,1,1,1 The 4th run: 0,0,0,0 The 5th run: 1,
Therefore the total number of runs is 5.
Any help would be much appreciated thanks

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回答（5 个）

Matt J
Matt J 2013-7-8
编辑：Matt J 2013-7-8
N_runs=nnz(diff(A))+1;
Azzi Abdelmalek
Azzi Abdelmalek 2013-7-8
numel(strfind(A,[0,1]))+ numel(strfind(A,[1,0]))+1
Jan
Jan 2013-7-8
David Sanchez
David Sanchez 2013-7-8
A=[1,1,1,0,0,1,1,1,1,0,0,0,0,1];
N_runs = 1;
for k=2:length(A)
if A(k)~=A(k-1)
N_runs = N_runs +1;
end
end
Matt J
Matt J 2013-7-8
编辑：Matt J 2013-7-8
If you have the Image Processing Toolbox,
C=bwconncomp([A,~A]);
N_runs=C.NumObjects;

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