using function with loop
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function [b, n, index] = RunLength(x)
d = [true; diff(x(:)) ~= 0]; % TRUE if values change
b = x(d); % Elements without repetitions
k = find([d.', true]); % Indices of changes
n = diff(k); % Number of repetitions
index = k(1:numel(k) - 1);
if iscolumn(x)
n = n.';
index = index.';
end
end
data = [1.2;1.0;0.05;0.4;0.3;0.2;0.1;0.05;0.04;0.03;0.03;0.02;0.01;0.001;0.01;0.01;0.001 ] ;
[b, n, index] = RunLength(data < 0.1);
match = find(b & n >= 10, 1);
result = index(match)
% This function find the number of row which 10 consecutive rows from the
% this computed row are smaller than 0.10. The result equals 8th row.
I need to use this function with loop such as;
data= 605x1 array includes numeric data
I need to compute the "result" with every 121 rows within 605 rows. So I need to run RunLength function five times (to produce five different result ) using the every 121 rows of the "data". I tried the below codes but it doesn't work;
i=1:121:605
for j=5
[b(:,j), n(:,j), index(:,j)] = RunLength(abs(data(i(j))) < 0.1);
match(j) = find(b(:,j) & n(:,j) >= 10, 1);
result(j) = index(match)
end
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采纳的回答
Jan
2021-4-26
编辑:Jan
2021-4-26
Result = zeros(1, 5);
iResult = 0;
for k = 1:121:605
datak = data(k:k+120);
[b, n, index] = RunLength(datak < 0.1);
match = find(b & n >= 10, 1);
iResult = iResult + 1;
Result(iResult) = index(match);
end
Maybe you have to catch the case, that match is empty.
Alternatively:
Result = zeros(1, 5);
iResult = 0;
for k = 1:5
index = (k - 1)*121 + 1;
datak = data(k:k+120);
[b, n, index] = RunLength(datak < 0.1);
match = find(b & n >= 10, 1);
Result(k) = index(match);
end
5 个评论
Jan
2021-4-27
编辑:Jan
2021-4-27
"Improper assignment with rectangular empty matrix." - this is the already mentioned problem, when match is empty. In the 2nd code you'd need to insert the isempty(match) check also.
You need to advance iResult even if match is empty:
size_data=numel(data);
repitition=size_data/121;
Result = zeros(1, repitition);
iResult = 0;
for k = 1:121:size_data
datak = abs(data(k:k+120));
[b, n, index] = RunLength(datak < 0.1);
match = find(b & n >= 20, 1);
iResult = iResult + 1; % Before the IF ISEMPTY(match) check
if isempty(match)
Result(iResult) = NaN;
else
Result(iResult) = index(match);
end
end
Or slightly simplified:
size_data=numel(data);
repitition=size_data/121;
Result = NaN(1, repitition); % NaN as default
iResult = 0;
for k = 1:121:size_data
datak = abs(data(k:k+120));
[b, n, index] = RunLength(datak < 0.1);
match = find(b & n >= 20, 1);
iResult = iResult + 1;
if ~isempty(match)
Result(iResult) = index(match);
end
end
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