sketch the graph of the function: f(x,y)= 1+2x^2+2y^2

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Ta Duc
Ta Duc 2021-5-2
回答： Carlos Guerrero García 2022-12-10
I'm not sure how to plot above equation. Can anyone help me?

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回答（2 个）

Jan
Jan 2021-5-2
Ran in:
fsurf(@(x,y) 1 + 2 * x.^2 + 2 * y.^2)
  2 个评论
Ta Duc
Ta Duc 2021-5-3
I don't think your answer is correct because it's different from the answer. Can u help me to do it again, tks a lot!
Jan
Jan 2021-5-3
@Ta Duc: Where do you see a difference? Matlab crops the object at rectangluar limits of the axis, in your image the object is cropped at a specific z value. Both methods are valid ways to display the object.
Do you see, that the formulas are identical?

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Carlos Guerrero García
Ran in:
The usage of polar coordinates must be useful:
[rho,theta]=meshgrid(0:0.1:2,0:pi/60:2*pi);
x=rho.*cos(theta);
y=rho.*sin(theta);
z=1+2*x.^2+2*y.^2;
surf(x,y,z);
shading interp;
axis equal % for a nice view

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