How to doI plot F(x) = [1 -(10/x)]/[1-(100/x^2)] for X ranging from 100 to 1100 at an interval of 50?

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Arpan Sow
Arpan Sow 2021-5-10
编辑： Jan 2021-5-10
F(x)= [1- (10/x)]/[1-(100/x^2)]

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回答（2 个）

Jan
Jan 2021-5-10
编辑：Jan 2021-5-10
x = 100:50:1100;
plot(x, (1 - (10 ./ x)) ./ (1 - (100 ./ x.^2)));
With some basic maths skills, a simplification is easy:
plot(x, 1 ./ (1 + (10 ./ x))
% Or better:
plot(x, x ./ (x + 10))
Stephan
Stephan 2021-5-10
Ran in:
F = @(x) (1-(10./x))./(1-(100./x.^2));
x_vals = 100:50:1100;
plot (x_vals, F(x_vals))

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