problem with name=value syntax
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the release notes for R2021a have name=value syntax.
I try it but it isn't working for me.
Error using experimental.mfetterman.MonteCarloStudy.testFunc>calcJ
Too many input arguments.
Error in experimental.mfetterman.MonteCarloStudy.testFunc (line 3)
calcJ(A=ark,B=bark);
ark=randn(5,3);
bark=randn(6,2);
calcJ(A=ark,B=bark);
function calcJ(A,B)
fprintf('rank A:%d\n',rank(A));
fprintf('rank B:%d\n',rank(B));
end
1 个评论
xingxingcui
2021-7-30
I think the way you wrote the call should be supported！there is no doubt in python and C++ languages
采纳的回答
That syntax is intended as a way to specify name-value pair arguments. So instead of:
plot(1:10, 1:10, 'Marker', 'o', 'LineStyle', ':')
you could write:
plot(1:10, 1:10, Marker = 'o', LineStyle = ':')
Your example does not use name-value pair arguments at all. What you wrote is:
calcJ(A=ark,B=bark); % equivalent to
calcJ('A', ark, 'B', bark);
Your calcJ function does not accept four inputs. It accepts two.
3 个评论
Matt Fetterman
2021-5-10
Steven Lord
2021-5-10
Either get rid of the names in your call:
ark=randn(5,3);
bark=randn(6,2);
calcJ(ark,bark);
function calcJ(A,B)
or modify your function so it accepts name-value pairs. The arguments keyword or inputParser will help you if you choose this approach.
xingxingcui
2021-7-30
Is it possible to enhance the new syntax "Name=Value Syntax" introduced in version R2021a?
It would be nice to have enhancements in future versions！
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