3D array becomes 4D Array

sia
2013 7 22
1 个回答
2 次查看（30 天）

0 个投票

Hi,
I use in matlab Simulink a matlab fcn blok to create a 3D array. That is the function:
function y = fcn()
X_welt=10;
Y_welt=10;
Z_welt=10;
welt = zeros(X_welt,Y_welt,Z_welt);
y = welt;
and I use additionally to workspace blok to load that into the matlab workspace. But the problem ist i get a 4D array val(:,:,1,1) =...
Why does it change the dimension???
THX

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回答（1 个）

Jan
Jan 2013-7-22

0 个投票

A trailing dimension of 1 can always be appended in Matlab. This still replies the 2nd element:
x = rand(3, 1);
disp(x(2, 1, 1, 1, 1, 1, 1, 1))
So please explain what "i get a 4D array val(:,:,1,1) =..." exactly means. Please post the complete code you use to identify the problem.

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sia
sia 2013-7-22
hi, as well as you see i create a 3D array with zeros. E.g.
>> a= zeros(2,2,2)
a(:,:,1) =
0 0
0 0
a(:,:,2) =
0 0
0 0
end
That works in matlab workspace. Now i wanna create this 3D array in Simulink matlab fcn blok and i wanna load it with "to workspace blok" into the matlab workspace. But the problme is i get everytime 1 dimension more than expacted. I get such like that:
val(:,:,1,1) =
0 0
0 0
val(:,:,2,1) =
0 0
0 0
val(:,:,1,2) =
0 0
0 0
.......
Jan
Jan 2013-7-22
Please do not post something, that is similar to what you get, but show us exactly what you get. What does size(val) return?
When you explain how you create this variable and how it is changed afterwards, we will find the reason for the results.
sia
sia 2013-7-23
I've already explained, i have a simulink model, and there i use matlab fcn block for creating a 3D array. i try to give the output to workspace. if i do that my 3D array becomes 4D array. maybe you can try it. use in simulink matlab fcn blok and create a 3D array like above, then the connenct the output with "to workspace" blok. and u can see the result in matlab workspace.

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sia
sia
2013-7-22

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