0 个投票

i have
x = [8, 9, -3, 9, 5, -4, -1, 3, 10, 10]
y = [-6; 4; 4; -2; 2]
z = diag(y)
how can i reconstruct matrix z into this look?
z =
-6 0 0 0 0 8
0 4 0 0 0 9
0 0 4 0 0 -3
0 0 0 -2 0 9
0 0 0 0 2 5
8 9 -3 9 5 -4
is there other way than this?
z = [-6 0 0 0 0 8; 0 4 0 0 0 9; 0 0 4 0 0 -3; 0 0 0 -2 0 9; 0 0 0 0 2 5; 8 9 -3 9 5 -4]

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Rik
Rik 2021-5-13
Where are the lower values coming from? Do you just want to put the values of x on the lower and right edges?
What have you tried to put them there?

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

Walter Roberson
Walter Roberson 2021-5-13
Ran in:

1 个投票

Ran in:
x = [8, 9, -3, 9, 5, -4, -1, 3, 10, 10];
y = [-6; 4; 4; -2; 2];
z = [diag(y), x(1:5).'; x(1:6)]
z = 6×6
-6 0 0 0 0 8 0 4 0 0 0 9 0 0 4 0 0 -3 0 0 0 -2 0 9 0 0 0 0 2 5 8 9 -3 9 5 -4

2 个评论
显示 无 隐藏 无

Hearthy Tampol
Hearthy Tampol 2021-5-13
thanks! didn't know there are other ways.
may I also ask how could I change its elements in a certain row for particular numbers?
example, i am planning to change the 4th row of matrix z with the with the last 6 elements of vector a?

请先登录，再进行评论。

更多回答（1 个）

David Hill
David Hill 2021-5-13

1 个投票

z=diag([y;0]);
z(end,:)=x(1:length(z));
z(:,end)=x(1:length(z));

类别

在 帮助中心 和 File Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息

产品

版本

R2021a

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by