Determine if a value is an Empty Matrix: 0 x 1 and replace with NaN

Question

Theodore 2013-7-23

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Hello. In my code I'm attempting to locate the max value of a variable. Unfortunately for doing max(variable) it gives an error if the matrix is a []. I was trying to figure out how to properly write my if else loop to put in NaN to a previously defined array if its a [] and if not, to calculate the value. My code is as follows:

if l == 1 
   fint=intersect(find(b(:,1)==k),find(b(:,2)==l))
if fint == []
          high_maxT_mo(k - (minyear-1),1) = NaN
          else
             high_maxT_mo(k - (minyear-1),1) = nanmax(maxtemp(fint))
          end
end

I get the following:

fint =

Empty matrix: 0-by-1

Error using == Matrix dimensions must agree.

Thanks!

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Theodore 2013-7-23

k is a variable defined in my for loop spanning from k=minyear:maxyear.

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Answer 1

Evan 2013-7-23

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/82963-determine-if-a-value-is-an-empty-matrix-0-x-1-and-replace-with-nan#answer_92570

编辑：Evan 2013-7-23

在 MATLAB Online 中打开

help isempty

Your code would look something like this:

if l == 1
    fint = intersect(find(b(:,1)==k),find(b(:,2)==l))
    if isemty(fint)
        high_maxT_mo(k - (minyear-1),1) = NaN
    else
        high_maxT_mo(k - (minyear-1),1) = nanmax(maxtemp(fint))
    end
end