ln not recognised as a command

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Niels
Niels 2013-7-25
Hello
I've entered the following formula in a function file:
heightModel = @(params,ages) (params(3)+params(4).*(ages/12)+params(5).*log((1+(ages/12))).*(1-exp(1).^(-exp(1).^(params(1)-params(2).*(ages/12))))+params(6).*exp(1).^(-exp(1).^(params(1)-params(2).*(ages/12)))); modelStrings = {'A','B','C','D','E','U'};
this works perfect but is not the good formula. The only thing that needs to change is the log in a ln
but if i do this i get the following error Undefined function 'ln' for input arguments of type 'double'.
Error in getModel/@(params,ages)(params(3)+params(4).*(ages/12)+params(5).*ln((1+(ages/12))).*(1-exp(1).^(-exp(1).^(params(1)-params(2).*(ages/12))))+params(6).*exp(1).^(-exp(1).^(params(1)-params(2).*(ages/12))))
Error in lsqcurvefit (line 199) initVals.F = feval(funfcn_x_xdata{3},xCurrent,XDATA,varargin{:});
Error in fitFilteredModel (line 13) [parameters,resnorm,residual,exitflag,output] = lsqcurvefit(heightModel,initialValues,filteredData(:,1),filteredData(:,2));
Error in main (line 43) fitFilteredModel(ages(i),models{k},genders{j},data,individualFit);
Caused by: Failure in initial user-supplied objective function evaluation. LSQCURVEFIT cannot continue.
Anyone willing to help me out. I'm a biologist so my coding knowledge is very limited.
Thanks

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采纳的回答

Iain
Iain 2013-7-25
You can fix it by putting:
ln = @(x)(log(x));
at the start of your code...
or replace ln with "log"

更多回答（1 个）

Evan
Evan 2013-7-25
编辑：Evan 2013-7-25
help log
If you read the help file for log, you'll see that it is the natural logarithm function. ln is not a built-in function. log10 is the function for computing the base-10 logarithm.

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