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How to change seconds since 1st January 1985 to YYYY-MM-DD-HR-M-S format?

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David
David 2013-7-29
I am a new user of MATLAB and was hoping to get some help to what is probably a very basic question to most of you. I am using data that currently represents time in seconds since 1st January 1985 and have been trying to change this to a format of YYYY-MM-DD-HR-M-S, however my attempts have been completely unsuccessful thus far. The data I am using ranges from 2003-2008. This is as much as I have come up with so far.
> t=86400; %86400 seconds in a day
> datestr(t/86400+datenum(1985,1,1))
Any help or guidance would be really appreciated. Cheers
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Jan
Jan 2013-7-29
What do you get as result of your code and what do you expect? I'd suggest exactly the same way, because it is the most efficient one.

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回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-7-29
编辑：Azzi Abdelmalek 2013-7-29
dat0='01-01-1985 00:00:00'
dat00=datevec(dat0,'dd-mm-yyyy HH:MM:SS')
a=95604
dat00(6)=dat00(6)+a
new_de=datestr(datenum(dat00))
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Jan
Jan 2013-7-29
Your dat00 contains the same information as David's datenum(1985,1,1). Adding the number of seconds to the 6.th component of the date vector is the same as adding t/86400 to the datenumber. Therefore I do not see the difference to the original approach.

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Iain
Iain 2013-7-29
seconds_since_1985 = 981364894; %
days_since_1985 = seconds_since_1985 / 86400;
datestr(days_since_1985 + datenum('1/1/1985'), 'YYYY-MM-DD-hh-mm-ss')
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Jan
Jan 2013-7-29
This looks also identical to the original version.
"MM" means minutes, while "mm" means months. So you have to swap upper- and lower-case.

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