how to use fsolve in for loop?

1 次查看(过去 30 天)
I need to pass different values of (theta_r) into F(1) and F(2) to get different values of x(1) and x(2).
i use this code, but it shows me many errors.
clear all;
%defining the parameters.
global R L3 L4 L5 theta_r
R=80; L5=360; L4=360; L3=120; n=2; m=100*n;
theta_r=linspace(0,2*pi*n,m);
function F = value(x,theta_r)
F(1)=R*sin(theta_r)+L3*sin(x(1))-L5*sin(x(2));
F(2)= R*cos(theta_r)+L3*cos(x(1))-L5*cos(x(2))-L4;
end
for b = 1:numl(theta_r)
x(b,:)=fsolve(@(x)value(x,theta_r(b),[1,0]));
end

采纳的回答

Jan
Jan 2021-5-20
编辑:Jan 2021-5-21
global R L3 L4 L5
R=80; L5=360; L4=360; L3=120; n=2; m=100*n;
theta_r=linspace(0,2*pi*n,m);
for b = 1:numel(theta_r) % fixed: "numl"
x(b,:) = fsolve(@(x) value(x, theta_r(b)), [1,0]);
end
function F = value(x,theta_r)
global R L3 L4 L5
F(1)=R*sin(theta_r)+L3*sin(x(1))-L5*sin(x(2));
F(2)= R*cos(theta_r)+L3*cos(x(1))-L5*cos(x(2))-L4;
end
  5 个评论

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by