For loop through a cell array

Hi, I need to calculate a for loop through a cell array. Each element has 5x5 matrixes. As seen in the code, I need to calculate a for loop in each element of D.
clc
clear all
N=5;
xn=linspace(2,4,N);
yn=xn;
for nx=1:N
for ny=1:N
E1(nx,ny)=xn(nx)*1i+(xn(nx)-yn(ny)^2);
E2(nx,ny)=(xn(nx)+yn(ny))*1i+xn(nx);
end
end
a11=E1.*conj(E1);
a12=E1.*conj(E2);
a21=E2.*conj(E1);
a22=E2.*conj(E2);
A=[a11 a12;a21 a22];
B={E1;E2};
C={conj(E1);conj(E2)};
D=cell(2,2);
for i=1:2
for j=1:2
D{i,j}=B{i}.*C{j};
end
end

3 个评论

Okay. What is your question?
Sir, as I mentioned at the top, I need to calculate a for loop for each element of D cell matrix. I don't know how to do it. This is an example code. There are E1,E2,...,E8. and each of them are 150x150 size. So my D cell matrix is 8x8 and each element is 150x150 matrix.
Your code seems to be fine for this job. So which problem do you want to solve now? In the code you use a {2 x 2} cell. If your real data are {8 x 8} simply change the code to:
D = cell(28, 8);
for i = 1:8
for j = 1:8
D{i,j} = B{i} .* C{j};
end
end

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回答(1 个)

Jonas
Jonas 2021-5-21

0 个投票

if you want to do a specific operation on each cell, then have a look into the cellfun() function

1 个评论

cellfun is nice and compact, but harder to code, more difficult to debug and it has a larger run time.

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提问:

2021-5-21

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Jan
2021-5-21

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