dynamically allocated c++ array covert-convert to mxArray

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Hello every one, i am new to matlab. So what i am trying to do is solve a problem like: Ax=B

I get a nXn matrix from my c++ code and i want to pass its values to mxArray. Specifically i do something like:

double **Ac = NULL;

Ac = new double*[size];

for(i = 0; i < size; i++){

Ac[i] = new double[size];

}

mxArray *Am = NULL;

Am = mxCreateDoubleMatrix (size, size, mxREAL);

memcpy( ( void* )mxGetPr(Am), ( void* )Ac, size*size*sizeof(double));

engPutVariable(ep, "Am",Am);

engEvalString(ep, "plot(Am);");

It shows a plot but not the correct one. Any directions?

Thank you all

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Answer 1

Jan 2013-7-31

在 MATLAB Online 中打开

0 个投票

Ac is not an array which contains the double values, but an array of pointers to vectors, which contain the values. If you prefer this nested kind of data storage for any good reasons, you need to copy the data vector by vector also:

double *Am_p;
Am_p = mxGetPr(Am);
for (i = 0; i < size; i++) {
  memcpy(Amp, Ac[i], size * sizeof(double));
  Amp += size;
}

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Pavlos 2013-7-31

Yes this seems right but i did it in a different way:

Ac = new double*[size];

Ac[0] = new double[size*size];

for (i=1; i < size ; i++){

Ac[i] = Ac[i-1] + size;

}

mxArray *Am = NULL;

Am = mxCreateDoubleMatrix (size, size, mxREAL);

memcpy( ( void* )mxGetPr(Am), ( void* )Ac[0], size*size*sizeof(double));

and it worked fine. Thanks a lot!

Jan 2013-7-31

I prefer storing matrices in one contiguous block also.

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dynamically allocated c++ array covert-convert to mxArray

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