Subexponential coding from c to matlab.

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I am having a C coding for the subexponential coding.Please tell me the matlab code written by me is correct and please suggest some ideas to implement the final step.
binary b= {k, if n<2^k
{floor(log2(n),if n>=2^k.
unary u= {0 if n<2^k
{b-k+1 if n>=2^k
Once these values are obtained, the code can be constructed by coding u in unary and continuing with the b LSB of n.
The matlab code written by me is as follows
function x=sec[n,k] %the value ok k is already estimated
if n<bitshift(2,k)
b=k;
u=0;
else
b=floor(log2(n));u=b-k+1;
x=[]%Once these values are obtained, the code can be constructed by coding u in unary and continuing with the b LSB of n.
I don't know to calculate x value in matlab.
The c code for calculating the code is given below
x =(((((1 < <( u )) -1) < < 1) < <( b )) | (n & ((1 < <( b )) -1)));
we build the unary code of u, which can be obtained by shifting a 1 bit u positions to the left and subtracting 1 to the result. A zero stop-bit can be added by shifting another position to the left the resulting value. The next operation is to append to this value the b LSB of n expressed in plain binary code. In order to do this the non-signicant bits of n must be discarded that is, theall-zero Most Signicant Bits (MSB) | by applying a mask that keeps the b LSB. A bit-wise OR operation with the truncated value of n will produce the required output.Once b and u are available, the subexponential code can be actually computed.
Please help me. Thankyou..
  4 个评论
dpb
dpb 2013-8-8
Not to mention you then came after me..._not_ how to make friends and win help... :(
Jan
Jan 2013-8-8
编辑:Jan 2013-8-8
@Pooja: Contributors, who do not like to be pushed, might tend to ignore your question as a reaction. Pushing causes the impression, that somebody thinks, that his time is more important than the time of others. But it is not surprising, that the others have a different opinion.

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