Given a linear system i want to do Gauss-Seidel iteration.But getting error.Would appreciate if anyone fix me the code. Thanks.

1 次查看（过去 30 天）
Abid Shahriar
Abid Shahriar 2021-5-30
编辑： KALYAN ACHARJYA 2021-5-30
>> x(1)=1.5;
>> y(1)=-1;
>> z(1)=1;
>> iter(1)=0;
>> for n=1:4
iter(n+1)=n;
x(n+1)=(16+3*y(n)-2*z(n))/8;
y(n+1)=(-9+2*x(n+1)-z(n))/8;
z(n+1)=(1+2*x(n+1)-4*y(n+1))/10;
end
>> Solution = [iter',x',y',z’]

请先登录，再回答此问题。

回答（1 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2021-5-30
No coding syntax error
x(1)=1.5;
y(1)=-1;
z(1)=1;
iter(1)=0;
for n=1:4
iter(n+1)=n;
x(n+1)=(16+3*y(n)-2*z(n))/8;
y(n+1)=(-9+2*x(n+1)-z(n))/8;
z(n+1)=(1+2*x(n+1)-4*y(n+1))/10;
end
Solution = [iter',x',y',z']
Result:
Solution =
0 1.5 -1 1
1 1.375 -0.90625 0.7375
2 1.4758 -0.84824 0.73445
3 1.4983 -0.84223 0.73655
4 1.5 -0.84206 0.73683
  3 个评论
显示 1更早的评论

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Systems Of Linear Equations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by