Given an integer number n (0<=n<10000), write a code returning the difference between the product of its digits and the sum of its digits.

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haneen yousef 2021-6-5

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评论： Walter Roberson 2021-6-5

Given an integer number n (0<=n<10000), write a code returning the difference between the product of its digits and the sum of its digits. For instance, if n=432 then the result is 4*3*2-(4+3+2) = 15.

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Walter Roberson 2021-6-5

编辑：Walter Roberson 2021-6-5

hints: https://www.mathworks.com/matlabcentral/answers/391891-find-numbers-whose-product-of-digits-is-6-times-the-sum-of-the-digits?s_tid=srchtitle

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SALAH ALRABEEI 2021-6-5

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编辑：SALAH ALRABEEI 2021-6-5

在 MATLAB Online 中打开

    % check this
a = 4321;
b=str2num(num2str(a)');
diff = abs(sum(b)- prod(b))

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SALAH ALRABEEI 2021-6-5

totally agree. Noted.

Walter Roberson 2021-6-5

@haneen yousef

That code seems to work when I test, except for 0 exactly.

For 0 exactly your Y would be 1 and your X would be 0 so you would get 1-0 = 1 as your solution, but for 0 exactly the product of the digits should be 0.

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