While loop and randomization
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Thank you in advance for your help!
if (valCount == ones)
disp(y1)
else
disp('repetition')
end
% this if/end works manually, but it's not a while loop, so it doesn't work
% automatically...
1 个评论
Jan
2021-6-7
Unfortuantely you have removed important parts of your question. Please don't do this. The nature of this forum is sharing problems and solution. The voluntary users spend time to help you and they want the thread to be useful for others also.
回答（1 个）
x = [1 1 1 2 2 2 3 3 3];
ready = false;
while ~ready
y1 = [x(randperm(numel(x))); x(randperm(numel(x))); x(randperm(numel(x)))];
ready = numel(unique(y1(:, 1))) == size(y1, 1);
end
Instead of a rejection you can use an constructive method:
x = [1 1 1 2 2 2 3 3 3];
nx = numel(x);
ux = unique(x);
nRow = 3;
y1 = zeros(nRow, nx);
for k = 1:nRow
v = x(randperm(nx));
v(find(v == ux(k), 1)) = [];
y1(k, :) = [ux(k), v];
end
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2021-6-6
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