exit from a nested loop
显示 更早的评论
Hi guys I have a problem with a inner loop:
Once the break command is read I correctly exit from the inner while loop but afterwards it does not increment i and consequently I cannot re-entering in the while loop.
How can I do that?
I guess break it is not the right command
for i=1:length(A)
counter2=0;
Xtot2=0;
Ytot2=0;
Xmean2 = 0;
Ymean2 = 0;
j=1;
while j <= length(F2)
if statement
break
end
if statement
counter2= counter2+1;
Xtot2= Xtot2 + F2{j,3};
Ytot2= Ytot2 + F2{j,4};
Xmean2 = (Xtot2/counter2);
Ymean2= (Ytot2/counter2);
H12{i,6}= Xmean2;
H12{i,7}= Ymean2;
end
end
end
2 个评论
Julius Muschaweck
2021-6-7
You may have another problem:
for i = 1:3
j = 0;
fprintf('i == %g\n',i);
while j <= i
j = j + 1;
fprintf('j == %g\n',j);
if j == 2
fprintf('break\n',j);
break
end
end
end
correctly tells me
i == 1
j == 1
j == 2
break
i == 2
j == 1
j == 2
break
i == 3
j == 1
j == 2
break
Riccardo Tronconi
2021-6-7
采纳的回答
"I correctly exit from the inner while loop but afterwards it does not increment i"
Why do you assume this? The outer loop is not influenced by breaking the inner loop.
"counter2 never returns to 0 whenever "break" command is read..."
Of course the break command breaks the inner loop and does not reset counter2 to 0. But this reset is does, when the outer loop runs its next iteration.
As far as I can see, your assumptions are not correct. USe the debugger to step through your code line by line to see, what's going on.
Note that your inner loop does not increment j anywhere. Therefore the condition "while j <= length(F2)" does not seem to be correct.
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