exit from a nested loop

7 次查看（过去 30 天）
Riccardo Tronconi
编辑： Jan 2021-6-7
Hi guys I have a problem with a inner loop:
Once the break command is read I correctly exit from the inner while loop but afterwards it does not increment i and consequently I cannot re-entering in the while loop.
How can I do that?
I guess break it is not the right command
for i=1:length(A)
counter2=0;
Xtot2=0;
Ytot2=0;
Xmean2 = 0;
Ymean2 = 0;
j=1;
while j <= length(F2)
if statement
break
end
if statement
counter2= counter2+1;
Xtot2= Xtot2 + F2{j,3};
Ytot2= Ytot2 + F2{j,4};
Xmean2 = (Xtot2/counter2);
Ymean2= (Ytot2/counter2);
H12{i,6}= Xmean2;
H12{i,7}= Ymean2;
end
end
end
  2 个评论
Julius Muschaweck
Julius Muschaweck 2021-6-7
You may have another problem:
for i = 1:3
j = 0;
fprintf('i == %g\n',i);
while j <= i
j = j + 1;
fprintf('j == %g\n',j);
if j == 2
fprintf('break\n',j);
break
end
end
end
correctly tells me
i == 1
j == 1
j == 2
break
i == 2
j == 1
j == 2
break
i == 3
j == 1
j == 2
break
Riccardo Tronconi
Riccardo Tronconi 2021-6-7
Yes! that's what I'm looking for!!
The other problem is that counter2 never returns to 0 whenever "break" command is read...
If I copy and past my code would you mind try to run on your side?

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Jan
Jan 2021-6-7
编辑：Jan 2021-6-7
"I correctly exit from the inner while loop but afterwards it does not increment i"
Why do you assume this? The outer loop is not influenced by breaking the inner loop.
"counter2 never returns to 0 whenever "break" command is read..."
Of course the break command breaks the inner loop and does not reset counter2 to 0. But this reset is does, when the outer loop runs its next iteration.
As far as I can see, your assumptions are not correct. USe the debugger to step through your code line by line to see, what's going on.
Note that your inner loop does not increment j anywhere. Therefore the condition "while j <= length(F2)" does not seem to be correct.

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by