find index in a matrix without 'find' function

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Naz khan
Naz khan 2021-6-12
编辑： Adam Danz 2021-6-14
I have an array of 1000+ samples. I want to find the index of nonzero elements in a large matrix in a shortest possible time. Whats the best way to get the list of indexing without using "find" funcion?
Example
p=[0 0 .34 0; 3 0 0 3; 0 9 0 0];
v=nonzeros(p)
for i=1:length(v)
[r,t]=find(p==v(i))
sds{i}=[r,t];
end;

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回答（1 个）

Adam Danz
Adam Danz 2021-6-12
编辑：Adam Danz 2021-6-14
Ran in:
find() is the quickest way to return the subscript indices of non-zero elements of a matrix but it's quicker to do so without using a loop. Is there a reason you can't use find?
p=[0 0 .34 0; 3 0 0 3; 0 9 0 0];
[rows, cols] = find(p~=0)
rows = 4×1
2 3 1 2
cols = 4×1
1 2 3 4
So, sds{i} is the same as [rows(i), cols(i)] but without repeats of the same value.

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