How to delete elements in array efficiently
显示 更早的评论
Hi all,
I'm writing a simple script in Matlab where I compare adjacent element and delete one of them if there difference between them is one.
for i=1:length(Vector) - 1
if Vector(i+1) - Vector(i) == 1
Vector(i) = [];
end
if i == length(Vector)
break
end
However, I'm getting an error that my indices are out of bound. Is there a simpler way of doing this by utilizing internal functions. I think my problem is that my array is constantly decreasing and the Vector(i+1) - Vector(i) are out of bounds.
采纳的回答
Azzi Abdelmalek
2013-8-25
Vector=[1 2 4 5 66 88 100 101]
id=find([0 diff(Vector)]==1)-1
Vector(id)=[]
更多回答（2 个）
When doing such in loops, start at end and work to beginning -- then the indices of those removed are above where you're headed next.
But, in Matlab use vector operations and supplied functions to do such things...
v([false diff(v)==1])=[];
Azzi Abdelmalek
2013-8-25
You can also do it with while loop
Vector=[1 2 3 4 5 66 88 100 101 14]
i=1;
while i<numel(Vector)
if Vector(i+1) - Vector(i) == 1
Vector(i) = [];
i=i-1;
end
i=i+1
end
Vector
4 个评论
dpb
2013-8-25
Or, variations on a theme, the looping solution...
for i=length(v):-1:2
if v(i)-v(i-1)==1;
v(i)=[];
end
end
Azzi Abdelmalek
2013-8-25
The result is not the same, because this will keep the first number of the consecutive numbers
Jan
2013-8-25
Repeated shrinking of an array suffers from the same inefficiency as iterative growing.
dpb
2013-8-26
Posted simply as pedagogical example for OP, not as recommended solution--see earlier posting.
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