Looping between two functions

Question

DARLINGTON ETAJE 2021-6-30

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/869068-looping-between-two-functions

评论： DARLINGTON ETAJE 2021-6-30

Hi. Please kindly help me solve this problem. the problem really lies from when ghs is mentioned.

function [bhs,ahs,cbs]=btime(t1,t2,t3)
    bhs=(t1*t2)+t3;
    ahs=t1+t3;
    cbs=t2./3;
end
function [abk,kba,t3]=ctime(bhs,cbs)
    abk=27.3.*bhs;
    kba=bhs+cbs;
    t3=35*(abk+kba);
end
    
wqe=[1;2;3;4;5;6;7;8;9;10;11;12;13;14;15];
kli=[51;52;53;54;55;56;57;58;59;60;61;62;63;64;65];
bbc=(21:1:35)';
hsd=size(kli,1);
kas=zeros(hsd,1);
sak=zeros(hsd,1);
cbb=zeros(hsd,1);
abc=zeros(hsd,3);
for i=1:hsd
    kas(i)=wqe(i);   
    sak(i)=kli(i);
    cbb(i)=bbc(i);
end
abc(1,:) = [kas(1) sak(1) cbb(1)];
for h=2:1:hsd    
    abc(h,:)=[kas(h) sak(h) cbb(h)];
end
matrix{1}=abc(1,:);
for i = 2:hsd
    matrix{i}=abc(1:i,:);
end
ghs=([]);
for iiv=1:1:hsd
    ghs(iiv)=(matrix{1,iiv}(:,:));
    t1=ghs(:,1);
    t2=ghs(:,2);   
    t3=ghs(:,3);
    [bhs(iiv),ahs(iiv),cbs(iiv)]=btime(t1(iiv),t2(iiv),t3(iiv))
    [abk(iiv),kba(iiv)]=ctime(bhs(iiv),cbs(iiv))
end
Final_Answer=[bhs kba]; % The goal is to put each new bhs and cbs under the previous one.

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Answer 1

Jan 2021-6-30

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https://ww2.mathworks.cn/matlabcentral/answers/869068-looping-between-two-functions#answer_736863

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Simplify your code:

for i=1:hsd
    kas(i)=wqe(i);   
    sak(i)=kli(i);
    cbb(i)=bbc(i);
end

does the same as:

kas = wqe;
sak = kli;
cbb = bbc;

The code:

abc(1,:) = [kas(1) sak(1) cbb(1)];
for h=2:1:hsd    
    abc(h,:)=[kas(h) sak(h) cbb(h)];
end

does the same as:

abc = [kas, sak, cbb];

The line:

ghs(iiv)=(matrix{1,iiv}(:,:));

is equivalent to:

ghs(iiv) = matrix{1,iiv};

But I do not see, why you create ghs as array at all.

It is not clear, what you want to achieve. With a simplified code this gets clearer, I hope, or if you explain this in detail.

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DARLINGTON ETAJE 2021-6-30

在 MATLAB Online 中打开

Thanks for your comments Jan. and you are right, some of those codes could be easier...take note that the size of ghs increases on every loop. The goal is to feed the new sets of t1, t2, and t3 to the two fucntions and finally produce Final_Answer. The newer bhs and kba are concatenated underneat. I know the process seems hard but I really need it. Thanks

Final_Answer=[bhs kba];

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