How to solve this issue Variable 'X' is not fully defined on some execution paths.

Question

Tony Castillo 2021-6-30

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/869088-how-to-solve-this-issue-variable-x-is-not-fully-defined-on-some-execution-paths

评论： Tony Castillo 2021-7-2

采纳的回答： Jan

在 MATLAB Online 中打开

Dear All,

I have a code into a MATLABFUNCTION block of Simulink that jump out this error message "

Variable 'CONDICIONTRAMO' is not fully defined on some execution paths. Function 'Battery_Control/Function_Cruz_v2' (#25.1881.1895), line 57, column 12: "CONDICIONTRAMO" Launch diagnostic report."

Anyone of you can help me out to find the way to solve this ? Please.

function [SOC_CC, Bat_charge] = BUsage(top, SOC, SOC_Seg, SOCint, W_demand, Power_PV)
if SOC>=SOC_Seg   
    SOC_CC=0;
    Bat_charge=0;
    return
else
    if SOC>=SOCint   
        SOC_CC=1;
        Bat_charge=0;
    end
    if SOC<=SOCint
        
        if (top>=8)||(top<=9) && Power_PV>W_demand 
            CONDICIONTRAMO = 1;
            disp('Llano 1 de 8 a 9')
        elseif (top>=8)||(top<=9) && Power_PV<W_demand
            CONDICIONTRAMO = 2;
            disp('"-" Llano 1 de 8 a 9')
            
        elseif (top>=10)||(top<=13) && Power_PV>W_demand
            CONDICIONTRAMO = 3;
            disp('Punta 1 de 10 a 13')
        elseif (top>=10)||(top<=13) && Power_PV<W_demand
            CONDICIONTRAMO = 4;
            disp('"-"Punta 1 de 10 a 13')
            
        elseif (top>=14)||(top<=17) && Power_PV>W_demand
            CONDICIONTRAMO = 5;
            disp('Llano 2 de 14 a 17')
        elseif (top>=14)||(top<=17) && Power_PV<W_demand
            CONDICIONTRAMO = 6;
            disp('"-"Llano 2 de 14 a 17')
            
        elseif (top>=18)||(top<=21)&& Power_PV>W_demand
            CONDICIONTRAMO = 7;
            disp('Punta 2 de 18 a 21')
        elseif (top>=18)||(top<=21)&& Power_PV<W_demand
            CONDICIONTRAMO = 8;
            disp('"-"Punta 2 de 18 a 21')
            
        elseif (top>=22)||(top<=23)&& Power_PV>W_demand
            CONDICIONTRAMO = 9;
            disp('Llano 3 de 22 a 23:59')
        elseif (top>=22)||(top<=23)&& Power_PV<W_demand
            CONDICIONTRAMO = 10;
            disp('"-"Llano 3 de 22 a 23:59')
            
        elseif (top>=24)||(top<=8) && Power_PV<W_demand
            CONDICIONTRAMO =11;
            disp('Valle de 24 a 8')
            
        end
        
        switch CONDICIONTRAMO
            case 1
                SOC_CC=1;
                Bat_charge=0;
            case 2
                SOC_CC=0;
                Bat_charge=0;
            case 3
                SOC_CC=1;
                Bat_charge=0;
            case 4
                SOC_CC=0;
                Bat_charge=0;
            case 5
                SOC_CC=1;
                Bat_charge=0;
            case 6
                SOC_CC=0;
                Bat_charge=0;
            case 7
                SOC_CC=1;
                Bat_charge=0;
            case 8
                SOC_CC=0;
                Bat_charge=0;
            case 9
                SOC_CC=1;
                Bat_charge=0;
            case 10
                SOC_CC=0;
                Bat_charge=0;
            case 11
                SOC_CC=1;
                Bat_charge=1;
            otherwise
                disp('No')
        end
    end
    
    
end
end

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Answer 1

Jan 2021-6-30

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/869088-how-to-solve-this-issue-variable-x-is-not-fully-defined-on-some-execution-paths#answer_736848

编辑：Jan 2021-6-30

在 MATLAB Online 中打开

Insert a definition of CONDICIONTRAMO = -1 (or NaN, or 12) either on top of the code, before the IF branchs, or in a finaly else branch:

...
        elseif (top>=24)||(top<=8) && Power_PV<W_demand
            CONDICIONTRAMO =11;
            disp('Valle de 24 a 8')
        else 
            CONDICIONTRAMO = 12;
        end            

But then Bat_charge is not defined in all branchs. Add a default value for this variable also.

By the way, the Switch/Case-Block is hard to read. Maybe this is tougher:

%               1 2 3 4 5 6 7 8 9 10 11 12
SOC_CC_V     = [1 0 1 0 1 0 1 0 1 0  1  NaN];
Bat_charge_V = [0 0 0 0 0 0 0 0 0 0  1  NaN];
SOC_CC     = SOC_CC_V(CONDICIONTRAMO);
Bat_charge = Bat_charge_V(CONDICIONTRAMO);