Amplitude vs frequency curve

12 次查看(过去 30 天)
Hey guys ! I would like your help to plot this frequency response function.
Just so you guys understand, I'm trying to plot the frequency response curve through ode45. I have a one degree of freedom system with its constants and I'm driving this system with a sinusoidal force that will do a frequency sweep.
I am sending the analytic result, as for my code attempt. The curve using the fft appears to be coherent, but the y axis has a very different unit.
function simulation
clear all
close all
clc
m = 0.086; % kg
k = 166.3629; % N/m
c = 0.1664 ; % N.s/m
F = 0.6385;% N
% Time
Fs=400;
tspan =0:1/Fs:250-1/Fs;
f0 = 4; % Hz
f1 = 9; % Hz
% analytical solution
w = f0:0.2:f1; %Hz
d1 = (k - m*(w*2*pi).^2).^2 + (c*w*2*pi).^2;
X = F./sqrt(d1);
% IC
x0 = 0; v0 = 0;
IC2 = [x0;v0];
% numerical integration
[time2,state_values2] = ode45(@h,tspan,IC2);
x = state_values2(:,1);
figure(1)
plot(time2,x),xlabel('time(s)'),ylabel('displacement(m)')
figure(2)
n=ceil(log2(length(x)));
fx=fft(x,2^n);
fx=2*fx/length(x); % This operation is Adjusting the Magnitudes
f=(Fs/2^n)*(0:2^(n-1)-1);
plot(f,abs(fx(1:2^(n-1))),w,X,'-.k'), xlabel(' Frequency (Hz)'), ylabel(' X (m)');
l1 = ' using fft';
l2 = ' analytical solution';
legend(l1,l2);
xlim([f0 f1])
end
function sdot1 = h(t,x)
m = 0.086; % kg
k = 166.3629; % N/m
c = 0.1664 ; % N.s/m
f0 = 4; % Hz
f1 = 9; % Hz
F = 0.6385;% N
a = (f1 - f0)/250;
sdot1 = [x(2);
(F.*sin(2*pi*(a*t/2 + f0)*t) - c.*x(2) - k*x(1))/m];
end
  4 个评论
Scott MacKenzie
Scott MacKenzie 2021-7-2
Is the y-axis magnitude really that important? Both solutions identify the signal at 7 Hz. Isn't that the key result? Sorry, if I'm completely off base here; this view is just based on my limited experience with spectrum analyses. I also notice that you resized the magnitudes after applying the fft. If you do so before, the result is closer to what you are looking for. Good luck.
x = rescale(x,-1, 1);
fx=fft(x,2^n);
José Anchieta de Jesus Filho
Thanks again for your help, but the y-axis is pretty important. I'm actually trying to plot the amplitude as a function of the excitation frequency. The analytical solution represents the amplitude as a function of the excitation frequency that this system will have, in steady state.

请先登录,再进行评论。

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Spectral Measurements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by