how to count no of zeros between ones

6 次查看(过去 30 天)
suppose my array is
a=[0 0 1 1 1 1 0 0 0 0 1 1 0 0 0 0 1 0 1 0 0]
output i want is
[2 4 4 1 2]

采纳的回答

Walter Roberson
Walter Roberson 2021-7-9
a=[0 0 1 1 1 1 0 0 0 0 1 1 0 0 0 0 1 0 1 0 0]
a = 1×21
0 0 1 1 1 1 0 0 0 0 1 1 0 0 0 0 1 0 1 0 0
starts = strfind([1 a], [1 0])
starts = 1×5
1 7 13 18 20
stops = strfind([a 1], [0 1])+1
stops = 1×5
3 11 17 19 22
stops - starts
ans = 1×5
2 4 4 1 2

更多回答(1 个)

Matt J
Matt J 2021-7-9
编辑:Matt J 2021-7-9

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