fetching data from array

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kash
kash 2013-9-19
I have a set of values as
G=[1 1 1 1 2 2 1 2 3 2 2 1 3 3]
in this there are 14 values,i want to fetch as following
there are 4 ones continously so i want to take first 1 ,then 2 2's continously ,i need first 2 ,then only 1 ,so i need to take that
So the output will be [1 2 1 2 3 2 1 3] with index positions [1 5 7 8 9 10 12 13]
kindly help

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Andrei Bobrov
Andrei Bobrov 2013-9-19
编辑：Andrei Bobrov 2013-9-19
G=[1 1 1 1 2 2 1 2 3 2 2 1 3 3];
G1 = G(:);
l = [true;diff(G1(:))~=0];
out = [G1(l),find(l)]

更多回答（1 个）

Jan
Jan 2013-9-19
编辑：Jan 2013-9-19
With: FEX: RunLength
[value, number, index] = RunLength(G)
Then value and index are the wanted results.
If you have problems to compile the fast MEX file, you can use RunLength_M from this submission instead. If you process millions of elements and runtime matters, be sure to use the compiled version.

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