fetching data from array
1 次查看(过去 30 天)
显示 更早的评论
I have a set of values as
G=[1 1 1 1 2 2 1 2 3 2 2 1 3 3]
in this there are 14 values,i want to fetch as following
there are 4 ones continously so i want to take first 1 ,then 2 2's continously ,i need first 2 ,then only 1 ,so i need to take that
So the output will be [1 2 1 2 3 2 1 3] with index positions [1 5 7 8 9 10 12 13]
kindly help
0 个评论
采纳的回答
Andrei Bobrov
2013-9-19
编辑:Andrei Bobrov
2013-9-19
G=[1 1 1 1 2 2 1 2 3 2 2 1 3 3];
G1 = G(:);
l = [true;diff(G1(:))~=0];
out = [G1(l),find(l)]
0 个评论
更多回答(1 个)
Jan
2013-9-19
编辑:Jan
2013-9-19
[value, number, index] = RunLength(G)
Then value and index are the wanted results.
If you have problems to compile the fast MEX file, you can use RunLength_M from this submission instead. If you process millions of elements and runtime matters, be sure to use the compiled version.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!