How to use multiple break statments
显示 更早的评论
In the below code if any of the error goes below the limit the loop break. But I want to break the loop if all of the conditions errors are below the defined limits. How can I modify this piece of code.
for i = 1:100
if(sln2.Error<=1)
break
else
% Update weights
Ext.W22=beta*Ext.W22;
Ext.W22List(i) = Ext.W22;
end
%% Convergance Check sub 2
sln3.Error=max(abs(Ext.P_gen_scaling-Ext.P_gen_scaling_3));
SLN3(i)=sln3;
if(sln3.Error<=0.1)
break
else
end
4 个评论
Rik
2021-7-14
When I format your question for you, it seems you're missing an end statement. Is this intentional?
Also, what exactly is your question? What exactly do you want to happen?
Sulaymon Eshkabilov
2021-7-14
As Rik mentioned above one "end" statement is missing. Moreover, the second "else" does nothing and thus, it should be removed.
for i = 1:100
if (sln2.Error<=1)
break
else
% Update weights
Ext.W22=beta*Ext.W22;
Ext.W22List(i) = Ext.W22;
end
%% Convergance Check sub 2
sln3.Error=max(abs(Ext.P_gen_scaling-Ext.P_gen_scaling_3));
SLN3(i)=sln3;
if (sln3.Error<=0.1)
break
end
end
Muhammad Qaisar Fahim
2021-7-14
Muhammad Qaisar Fahim
2021-7-14
采纳的回答
更多回答(1 个)
Jan
2021-7-14
for i = 1:100
Ext.W22 = beta * Ext.W22;
Ext.W22List(i) = Ext.W22;
%% Convergance Check sub 2
sln3.Error = max(abs(Ext.P_gen_scaling - Ext.P_gen_scaling_3));
SLN3(i) = sln3;
if (sln3.Error <= 0.1) && (sln2.Error <= 1)
break
end
end
1 个评论
Muhammad Qaisar Fahim
2021-7-14
编辑:Muhammad Qaisar Fahim
2021-7-14
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