i was given a an image with black lines on white background . what i need to do is, to find the coordinates of the edges at the intersection of black lines..can u plz suggest a way to start with....plzz

Question

srinivas sri 2013-9-22

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/87901-i-was-given-a-an-image-with-black-lines-on-white-background-what-i-need-to-do-is-to-find-the-coor

采纳的回答： Image Analyst

ls

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Image Analyst 2013-9-22

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/87901-i-was-given-a-an-image-with-black-lines-on-white-background-what-i-need-to-do-is-to-find-the-coor#answer_97508

Threshold. If you want to find centroids of the crossing points, skeletonize with bwmorph(), then find crossing points with bwmorph().

If you have thick lines and want to find the "edges" of the intersection you need to define that. Do you mean just the 4 coordinates at the corners? Or do you mean the quadrilateral of all 4 straight edges where the two thick lines cross? How thick are these lines? Why do you want the edges instead of the center coordinate of where they cross?

You forgot to attach your image. Please do so.

2 个评论
显示无隐藏无

srinivas sri 2013-9-22

what i mean is the coordinates of points at which horizontal and vertical lines meet ...

Image Analyst 2013-9-22

test.m

The attached file will get you 95% of the way there. I didn't do the last 5% because I think this may be a homework assignment and you need to do something on it.

请先登录，再进行评论。

Answer 2

Matt J 2013-9-22

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/87901-i-was-given-a-an-image-with-black-lines-on-white-background-what-i-need-to-do-is-to-find-the-coor#answer_97509

编辑：Matt J 2013-9-22

在 MATLAB Online 中打开

As a start, the following will separate the image into a binary image H of horizontal lines and V of vertical lines.

A=double(rgb2gray(imread('sid.png'))<10); 
   e=ones(1,7);
   H=conv2(A,e,'same')>3;
   V=conv2(A,e.','same')>3;

3 个评论
显示 1更早的评论隐藏 1更早的评论

Matt J 2013-9-22

编辑：Matt J 2013-9-22

Yes. I gave you the first step. Neither I, nor Image Analyst, nor anyone else here, I believe, will give you the whole thing. But... consider the FIND command.

srinivas sri 2013-9-22