convert logical cell array to double
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I have a 4×1 logical cell array and each element is also a 2×1 cell array. So there are 8 elements total. I want to convert them all to double and vertically merge them. I tried the following but I couldn't:
cellfun(@(x) vertcat(double(x)), mycell,'uni',0)
the error is:
??? Error using ==> double
Conversion to double from cell is not possible.
2 个评论
the cyclist
2011-6-4
It is not 100% clear to me what you mean by a "logical cell array", or quite what the contents look like. Is it that mycell is a 4x1 cell array, and the content of each of the four elements is a 2x1 cell array, and the contents of each element of those 2x1's is a logical scalar? Would it be possible for you to include an example of "mycell", to be clearer?
Any chance you could change the construction of the variables upstream, so that it is not so convoluted?
回答(3 个)
Walter Roberson
2011-6-4
0 + cell2mat(vertcat(mycell{:}))
6 个评论
Walter Roberson
2011-6-5
60 x 63 is not a fit horizontally or vertically.
How do you want to proceed from here?
Also, do you want the result to be N x 79, or N x (79 * 2)? It isn't clear whether you want the groups of 2 x 1 to be arranged vertically (giving N x (79 * 2)), or if you want everything to be stacked as if a single N x 79 array? If everything is to be stacked, you need to define the relative order for the pieces.
Jan
2011-6-6
@Walter: You can omit the "0" in "0+cell2mat(vertcat(mycell{:}))". "+TRUE" is a DOUBLE.
Matt Fig
2011-6-4
If A is your array,
B = [A{:}]; % Step 1.
B = [B{:}] % Step 2.
This will only work if each of the logical arrays in each cell are the same size in the row direction. If instead they are all the same size in the column direction, try this:
B = [A{:}]; % Step 1.
B = vertcat(B{:}) % Step 2.
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