how to find z transform of a random sequence?

1 次查看（过去 30 天）
vikash
vikash 2013-9-23
hello, i wish to find out z transform expression of a huge sequence say 500 elements as it is required for some modelling in my project. if we have few elements, say [1 2 6 1 5], we can write the form as 1+2/z+6/z^2+1/z^3+5/z^4. But how to do this in case of large sequences, sure i don't want to manually write like the above one for all the elements. Please help!!!!!!
thanks in advance

请先登录，再回答此问题。

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-9-23
编辑：Azzi Abdelmalek 2013-9-23
h=randi(10,1,500);
syms z zz
zz=1;
H=0;
for k=1:numel(h)
zz=zz*z^-1;
H=H+h(k)*zz;
end
%or maybe
h=randi(20,1,500); % Example
H=tf(0,1,1);
D=1;
for k=1:numel(h)
D=conv(D,[1 0]);
H=H+tf(h(k),D,1);
end

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 z-transforms 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by