Creating array from binary sequence, and certainly with the calculation of the dimension

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FRANCISCO 2013-9-26

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/88292-creating-array-from-binary-sequence-and-certainly-with-the-calculation-of-the-dimension

编辑： Azzi Abdelmalek 2013-9-26

采纳的回答： Azzi Abdelmalek

I have this sequence:

0 (1) 0 (2) 0 (3) 1 (4) 1 (5) 0 (6) 0 (7) 0 (8) 0 (9) 0 (10) 1 (11) 0 (12)

0 (13) 0 (14) 0 (15) 1 (16) 0 (17) 0 (18) 1 (19) 1 (20).

As I can create an array like this in general, ie can perform instead of substrings of length 3, 4,5,6 .... too long? I have doubt through command for creating the dimension of the matrix, and I want you to believe me automatically. The matrix example is:

0 (18) 1 (19) 1 (20)

0 (15) 0 (17) 1 (19)

0 (12) 0 (15) 0 (18)

0 (9) 0 (13) 0 (17)

0 (6) 1 (11) 1 (16)

0 (3) 0 (9) 0 (15)

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Azzi Abdelmalek 2013-9-26

编辑：Azzi Abdelmalek 2013-9-26

Your question is not clear. Is the matrix you want to create always an nx3 size?

FRANCISCO 2013-9-26

I from the first sequence of data, I want to create an array with that order. No nx3 always no, I have posibildad nX4, nX5, nX6 ........ How could I do?

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Answer 1

Azzi Abdelmalek 2013-9-26

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/88292-creating-array-from-binary-sequence-and-certainly-with-the-calculation-of-the-dimension#answer_97842

编辑：Azzi Abdelmalek 2013-9-26

在 MATLAB Online 中打开

A=randi([0 1],1,30); % your array
m=5; % the result will be nx5
n=numel(A);
p=n-m+1:-m:1;
np=numel(p);
B=zeros(np,m);
B(:,1)=p';
mm=m;
for k=2:m
  mm=mm-1;
  B(:,k)=(n-m+k:-mm:n-m+k-mm*(np-1))';
end
disp(B) % matrix of indices
out=A(B)