Same Function but Different Result (Basic Function)
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Hi all, can anybody help me ? I have 2 same functions here, but when I evaluate them, I got a slightly different result. Perhaps someone could help me to check it ? Thank you
The first version is
t = [4:1:14];
A0 = 23
rho = 1.2
Ton = 1.2
Toff = 6
r = 0.6
del_a = 3.8
del_m = 0.1
p = t>=Ton;
q = t <Toff;
s = t>=Toff;
A = (A0*exp(rho.*(t - Ton)).*p.*q) + (A0*exp(rho*(Toff - Ton))*exp(-(r+del_a).*(t - Toff))).*s;
M = ((r/(r+del_a - del_m))*(A0*exp(rho*(Toff - Ton))*exp(-del_m.*(t-Toff)) - A)).*s;
y = A+M
plot(t,y)
and the second version is :
t = [4:1:14];
Par(1) = 23
Par(2) = 1.2
Par(3) = 1.2
Par(4) = 6
Par(5) = 0.6
Par(6) = 3.8
Par(7) = 0.1
model = @(Par,t) ( ( Par(1)*exp(Par(2).*(t - Par(3))).*(t>=Par(3)).*(t < Par(4)) )...
+ ( Par(1)*exp(Par(4) - Par(3))*exp(-(Par(5)+Par(6)).*(t - Par(4))).*(t >= Par(:,4)))...
+ ( (Par(5)/(Par(5) + Par(6) - Par(7))) *( (Par(1)*exp(Par(2)*(Par(4) - Par(3))))* ...
exp(-Par(7).*(t - Par(4))) - (( Par(1)*exp(Par(2).*(t - Par(3))).*(t>=Par(3)).*(t < Par(4)) )...
+ ( Par(1)*exp(Par(4) - Par(3))*exp(-(Par(5)+Par(6)).*(t - Par(4))).*(t >= Par(4)))...
) ) ).*(t>=Par(4)) ...
)
y = model(Par,time);
plot(t,y)
the problem is I have a slightly different result, but both of them are a same function. Can anybody help ? What I want to do is to convert my function in the first version into a function handle like in the second version
Thanks very much
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采纳的回答
If I replace "time" by "t", I get this:
y1 = A+M;
y2 = model(Par, t);
y1 - y2
% >> 0, 0, 3875.769e, 47.58413, 0.5842066, 7.172503e-3, 8.805925e-5, 1.081133e-6, 1.327351e-8, 1.629701e-10, 1.989520e-12
This seems to show, that the functions are different.
The 2nd version is very hard to read. I'd really avoid such ugly code, because, as you already see, it is nearly impossible to debug it. Do you have any good reasons to prefer this kind of code?
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