Convert a matrix to { }

2013 10 6
3 个回答
更新时间：2013 10 7
11 次查看（30 天）

0 个投票

Can anyone help me to convert a matrix that is for instance:
0 1 2
3 4 5
6 7 8
called symbols obtained from an image to something that is in the following form symbols= {'0' '1' '2' '3' '4' '5' '6' '7' '8'}.

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回答（3 个）

Jan
Jan 2013-10-6
编辑：Jan 2013-10-6

0 个投票

symbols = [0 1 2; ...
3 4 5; ...
6 7 8];
S = sprintf('%g*', symbols.');
S(end) = []; % Remove trailing *
C = regexp(S, '*', 'split');
Another simpler method:
C = cell(1, numel(symbols));
symbols = symbols.';
for iC = 1:numel(symbols)
C{iC} = sprintf('%g', symbols(iC));
end
I'm not convinced, that the conversion will really help to solve your problem.
Jan
Jan 2013-10-6

0 个投票

Or:
symbols = [0 1 2; 3 4 5; 6 7 8];
C = num2cell(char('0' + symbols.'))

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Jan
Jan 2013-10-6
This fails when any element of the input is outside [0, 9].

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Andrei Bobrov
Andrei Bobrov 2013-10-6
编辑：Andrei Bobrov 2013-10-7

0 个投票

A = [0 1 2
3 4 5
6 7 8];
cellstr(sprintf('%d',A')')'
other variant:
regexp(num2str(reshape(A.',1,[])),'\d*','match')

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Jan
Jan 2013-10-6
编辑：Jan 2013-10-6
This fails when any element of the input is outside [0, 9].
Andrei Bobrov
Andrei Bobrov 2013-10-7
编辑：Andrei Bobrov 2013-10-7
Hi Jan, I agree with you and I suggest another option.

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