How to link two functions

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Nikhil
Nikhil 2013-10-10
评论: sixwwwwww 2013-10-11
Hello all,
I am want to link following two programs: In first program(trial.m), I am calling fsolve function to solve for system of non linear equations which is stored in second function loaddistr. The two functions trial.m and loaddistr.m are as follows:
%trial curvesumi=0.2017; curvesumo=0.1377; distar=0.6031; dostar=0.6577; mateprop=1e-4*[0.1011 0.0910];
ki=(2/(curvesumi*distar))^(3/2).*curvesumi./(1.5.*mateprop);
ko=(2/(curvesumo*dostar))^(3/2).*curvesumo./(1.5.*mateprop);
Kn=(1./((1./ki).^(1/1.5)+(1./ko).^(1/1.5))).^1.5;
m0=[0.35,0.15,0.05];
p=fsolve(@loaddistr,m0);
function n = loaddistr( m ) Fr=8900; Pd=0.015; Z=9;
Kn=3.5893e+005;
Jr=[0.1156,0.1590,0.1892,0.2117,0.2288,0.2416,0.2505,0.2559,0.2576,0.2546,0.2289,0.1871,0.1339,0.0711];
eps=[0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.25, 1.67, 2.5, 5.0];
n=[m(1)-0.5*(1-0.5*Pd/m(3));
m(3)-Pd/2-(Fr/(Z*Kn*m(2)))^(1/1.5);
m(2)-spline(eps,Jr,m(1))];
end
If you notice I am using Kn term in both programs. I want to transfer this Kn value directly from trial.m to loaddistr.m, without separately specifying it in loaddistr.m So can someone please guide me about the code which will allow me to solve for loaddistr.m by using the Kn value from trial.m.
Thanks in advance,
Nikhil
  9 个评论
sixwwwwww
sixwwwwww 2013-10-11
wait i do it for you. Surely you can't define function like this. I do it wait

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采纳的回答

sixwwwwww
sixwwwwww 2013-10-11
Hey here is your merged code:
curvesumi = 0.2017;
curvesumo = 0.1377;
distar = 0.6031;
dostar = 0.6577;
mateprop = 1e-4 * [0.1011 0.0910];
ki = (2 / (curvesumi * distar)) ^ (3 / 2) .* curvesumi ./ (1.5 .* mateprop);
ko = (2 / (curvesumo * dostar)) ^ (3 / 2) .* curvesumo ./ (1.5 .* mateprop);
Kn = (1 ./ ((1 ./ ki) .^ (1 / 1.5) + (1 ./ ko) .^ (1 / 1.5))) .^ 1.5;
m0 = [0.35, 0.15, 0.05];
Fr = 8900;
Pd = 0.015;
Z = 9;
Jr = [0.1156, 0.1590, 0.1892, 0.2117, 0.2288, 0.2416, 0.2505, 0.2559, 0.2576, 0.2546, 0.2289, 0.1871, 0.1339, 0.0711];
eps = [0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.25, 1.67, 2.5, 5.0];
n = [m0(1) - 0.5 * (1 - 0.5 * Pd / m0(3));
m0(3) - Pd / 2 - (Fr / (Z * Kn(1) * m0(2))) ^ (1 / 1.5); % for first value of Kn
m0(3) - Pd / 2 - (Fr / (Z * Kn(2) * m0(2))) ^ (1 / 1.5); % for second value of Kn
m0(2) - spline(eps, Jr, m0(1))];
  16 个评论
Nikhil
Nikhil 2013-10-11
Haha. I will work that out. Anyways thanks a lot for your help.
sixwwwwww
sixwwwwww 2013-10-11
You are always welcome. If you have further problems you can share as well. Good luck!

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