How to find the difference b/w two string time and to convert in to seconds.

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Manu MJ
Manu MJ 2011-6-8
In my code time data is as given below. eg. '12.56.13' 12.57.39'. Now how to find the difference b/w the two given time and to convert the obtained value in to seconds. How to pass the obtained seconds to timer. I am having time data of size 45 lake rows. I want efficient way to find the above.
Regards Manu M.J

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采纳的回答

Walter Roberson
Walter Roberson 2011-6-8
datenum() the strings, subtract. To convert the time difference to seconds, multiply by 24*60*60 (number of seconds in a day). To "pass" the obtained seconds to a timer, set the timer StartDelay property to that number of seconds -- and remember to start() the timer.

更多回答（2 个）

Jan
Jan 2011-6-8
More efficient than DATENUM:
t1 = '12.56.13';
t2 = '12.57.39';
t1num = [3600, 60, 1] * sscanf(t1, '%d.');
t2num = [3600, 60, 1] * sscanf(t2, '%d.');
tdiff = t2num - t1num;
I do not know what "45 lake rows" are, but you can adjust the above method to all kind of inputs.
Manu MJ
Manu MJ 2011-6-8
Datenum('12.36.15') is not functioning. Error is appearing as:
Error using ==> datenum at 174
DATENUM failed.
Caused by: Error using ==> datevec at 286 Cannot parse date 2.3.4

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