How to correct the error Matlab says i've done?
1 次查看(过去 30 天)
显示 更早的评论
bsd Hello, here are the codes i'm using, Avodakodnew is the one i run, euler is needed for Avodakodnew. Here is the error i get when i try to run it:
>> Avodakodnew(5.5)
Subscripted assignment dimension mismatch.
Error in Avodakodnew (line 46) gu(i,j) = etha * ku(i,j) * diff ( u(i,j+1) - u(i,j), t ); %upper
What does this mean?
When i do >> ndims(gu), i get:
ans = 2
but if i ask for >> ndims(gu(i,j)), i get an error:
Subscript indices must either be real positive integers or logicals.
Anybody could help me to understand and correct that,please?
0 个评论
采纳的回答
Walter Roberson
2013-10-18
Your c6 is a vector or matrix but you are trying to assign it into the single location gu(i,j). Or possibly c6 is empty.
We need to know: are the "u" values symbolic or numeric? If they are symbolic then diff(c3,t) makes sense in itself, but each "gu" will be symbolic when generated. If the "u" values are numeric, then diff(c3,t) is going to ask for the "t'th" numeric difference, and since you are passing in a scalar expression, if "t" does not happen to be a positive integer you would get an error message from diff(), and if "t" does happen to be a positive integer, then the diff() of a scalar is going to be empty.
1 个评论
Walter Roberson
2013-10-21
You cannot differentiate a numeric vector with respect to time. When you apply diff() to a numeric vector, you get the Difference function, not Differentiation. diff(x) with no second argument and with x numeric, means
[x(2:end) - x(1:end-1)]
It is possible that you want to know the gradient in numeric form. If so and if "t" is a vector of time values that correspond to u values, use gradient()
更多回答(6 个)
Andreas Goser
2013-10-16
编辑:Andreas Goser
2013-10-16
Could be multiple things in
etha * ku(i,j) * diff ( u(i,j+1) - u(i,j), t );
My gut feeling is you want to use .* instead of * in at least one of the operations.
2 个评论
Andreas Goser
2013-10-16
I can keep on guessing like you use i and j without assigning them first and MATLAB treats them as complex numbers, but first and foremost, in order to resolve this one needs code AND data.
Jan
2013-10-16
编辑:Jan
2013-10-17
The problem is concealed anywhere in this line. So split the line into its parts to find out, where the problem is:
c1 = u(i,j+1);
c2 = u(i,j);
c3 = c1 - c2;
c4 = diff(c3, t);
c5 = etha * ku(i,j);
c6 = c5 * c4;
gu(i,j) = c6;
Now find out which step fails.
4 个评论
Image Analyst
2013-10-18
I don't know what bsd means, but this will help http://blogs.mathworks.com/videos/2012/07/03/debugging-in-matlab/. That will definitely solve it but in case you don't want to do that, you can put these lines before that gu line:
whos i
whos j
whos c6
Siavash Kardar Tehran
2013-10-17
firt of all make sure when you're using "for" command the vectors start their indices from 1, I mean Matlab doesn't recognize gu(0) and it must start at gu(1);
also make sure u(i,j+1) doesn't exceed you matrix dimensions.
I hope this could help.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Multidimensional Arrays 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!