0 个投票

I use the following code to open a hex file (please look at the attachment).
fid = fopen('FileName');
A = fread(fid);
My problem is instead of getting A as a cell containg n*1 (n is the number of rows in the hex file) I get one row of numbers. I would appreciate it if you help me get a result like below:
00 00 00 00 49 40 40 0D
03 00 30 43 C6 02 00 00
A3 6B 74 23 90 47 E4 40
and so on

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Azzi Abdelmalek
Azzi Abdelmalek 2013-10-16
Can you post the result you've got? maybe with simple use of reshape function you can get the expected result

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Jan
Jan 2013-10-16
编辑：Jan 2013-10-16

5 个投票

There is not format you can call "hex file". You can interpret a file as stream of bytes and display them by hex numbers. But from this point of view, any file is a hex file.
Please try this:
fid = fopen('FileName');
A = fread(fid, Inf, 'uint8');
fclose(fid);
Fmt = repmat('%02X ', 1, 16); % Create format string
Fmt(end) = '*'; % Trailing star
S = sprintf(Fmt, A); % One long string
C = regexp(S, '*', 'split'); % Split at stars
Perhaps a string with line breaks is sufficient:
Fmt = repmat('%02X ', 1, 16); % Create format string
Fmt(end:end+1) = '\n';
S = sprintf(Fmt, A);

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Ronaldo
Ronaldo 2013-10-16
When the file is large, I get the following error for line 2:
OUT of MEMORY
Jan
Jan 2013-10-16
@Ronaldo: Please specify "large". Some people in the forum use this for 1000 elements, some for 1e15 elements.
When importing the file exhausts too much memory, install more memory, use a 64 bit version of Matlab and OS, free arrays, which are not used anymore. You can import the data by fread(fid, Inf, '*uint8') also, which occupies just an 8.th of the memory. But for SPRINTF a modern Matlab version is required then, because older ones did not accept UINT8 as input.
Ronaldo
Ronaldo 2013-10-17
The file that I want to open is 5 GB. I am using a 64 bit version of MATLAB and OS. Available physical memory of my computer is 31.2 GB. I was wondering whether there is anyway that I can prevent OUT of MEMORY problem if I want to open the 5 GB file.

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Azzi Abdelmalek
Azzi Abdelmalek 2013-10-16
编辑：Azzi Abdelmalek 2013-10-16

1 个投票

fid = fopen('file.txt');
A = textscan(fid,'%s %s %s %s %s %s %s %s')
fclose(fid)
A=[A{:}]
arrayfun(@(x) strjoin(A(1,:)),(1:3)','un',0)

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Walter Roberson
Walter Roberson 2013-10-16
Use '%x%x%x%x%x' instead of %s if the numeric form is desired.
Ronaldo
Ronaldo 2013-10-16
编辑：Ronaldo 2013-10-18
The extension of the original file is not txt.
Ronaldo
Ronaldo 2013-10-16
编辑：Ronaldo 2013-10-16
If I use the following code for the problem, I get the result that I want
fid = fopen('FIleName');
a = fread(fid);
for i=1:size(a,1)
sprintf('%02X %02X %02X %02X %02X %02X %02X %02X %02X %02X %02X %02X %02X %02X %02X %02X',a(8*i-7:8*i,1))
end
BUT if the file size is large then this code is not working. This is the reason why I want "a" to be (n*1 cell which each cell contains one row of the image attached to the question) instead of a complete row or column. of all the elements in the hex file.
Azzi Abdelmalek
Azzi Abdelmalek 2013-10-16
编辑：Azzi Abdelmalek 2013-10-16
Post the first samples you've got with
A = fread(fid);
Azzi Abdelmalek
Azzi Abdelmalek 2013-10-16
If the data you've got are like:
A={'00' ;'00' ;'00';'00'; '49'; '40' ;'40' ;'0D'; '03'; '00' ;'30' ;'43'; 'C6'; '02'; '00' ;'00'}
You can make some transformations
out=reshape(A,8,[])'
result=arrayfun(@(x) strjoin(out(x,:)),(1:size(out,1))','un',0)
Ronaldo
Ronaldo 2013-10-16
编辑：Ronaldo 2013-10-16
It is a column of double numbers. If I use dec2hex for each element of the column, I get the equivalent value in the original hex file. As you can see in the attachment the hex file contains different rows, I like "a" also contains several rows to avoid memory leak!
Azzi Abdelmalek
Azzi Abdelmalek 2013-10-16
编辑：Azzi Abdelmalek 2013-10-16
Decimal numbers? please edit your question and make it as clear as possible
Jan
Jan 2013-10-16
@Ronaldo: A memory leak? I assume, you mean something completely different.

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