Disabling printing underscore as subscript in figures
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Underscores print as subscript in figures. Can I disable it because I want to print the underscores as well.
Thanks.
2 个评论
Michael Marcus
2019-4-11
编辑：Stephen23
2019-4-11
Although this allows underscores to print, it does not allow special symbols such as \mum to work.. Does anyone know how to allow both.
Mike Marcus
Michael Marcus
2019-4-11
I did find out another way to keep the underscore. \_ does work ? I have answered my own question? Convert all underscores in the text to \_ instead of changing the interpreter to none.
采纳的回答
Walter Roberson
2011-6-11
编辑：Image Analyst
2018-1-17
Set the Interpreter property for that field to 'none'; the default for text() fields is LaTex.
title('This_title has an underline', 'Interpreter', 'none'); % Also works with xlabel() and ylabel()
13 个评论
AP
2011-6-11
AP
2011-6-11
编辑：Walter Roberson
2023-5-9
Walter Roberson
2011-6-11
编辑：Walter Roberson
2023-5-9
Personally I never count on gco being the object I am interested in.
In the above, gco is likely to be the result of imshow(), but imshow() returns an image object, and image objects do not have a 'text' field.
When you title(), a _new_ text object is created to hold the title. That new text object is not going to inherit the properties of the old one.
I would suggest,
for i = 1:4
subplot(2,2,i)
imshow(im{i})
title(sprintf('%s_%d',mytitle{i},i), 'Interpreter', 'none');
end
AP
2011-6-11
Jan
2011-6-11
Another method: Replace '_' by '\_' in the string.
Addo
2018-2-13
How can I use this for the legend of a plot? I have a string with underscores that I would like to use for the legend. I don't want to change it to "\_" and 'Interpreter', 'none' doesn't work with legend('show').
AM
2018-4-12
编辑：Walter Roberson
2018-4-12
try something like this:
leg=legend('data1','data2','data3');
set(leg,'Interpreter', 'none')
Walter Roberson
2018-4-12
编辑：Walter Roberson
2023-5-9
@AM is correct: although legend() does not accept that name/value pair, you can set it on the handle.
Yulong Li
2023-5-9
It looks like it does not work for stackedplot:
title(filename, 'Interpreter', 'none');
It returns error:
Error using matlab.graphics.chart.Chart/title
Too many input arguments specified when using title with stackedplot.
Is there a way to disable understcore in stackedplot title?
Walter Roberson
2023-5-9
It appears that stackedplot treats titles differently. The great majority of plot types are within axes, and in those cases the axes has a Title property that is a text() object. But stackedplot() does not use axes: it is a direct parent of a figure, and the Title property for it is a character vector, with there being no Interpreter property.
It appears that you need to use the method suggested by @Jan in https://www.mathworks.com/matlabcentral/answers/9260-disabling-printing-underscore-as-subscript-in-figures#comment_20281 -- namely to replace the _ with \_
title(regexprep(filename, '_', '\\_'))
Yulong Li
2023-5-9
@Walter Roberson got it, thanks!
Eliot
2025-4-16
Thank you for this easy solution to my messed-up plot titles!
更多回答（1 个）
HE
2020-5-5
If you are using sprintf, \\_ should work for you.
Example from https://www.mathworks.com/matlabcentral/answers/94238-how-can-i-place-the-_-or-characters-in-a-text-command#comment_327816:
old_cells = sprintf('Old cells: Y = %3.3f (X) \\^ %1.3f',coefs_old);
young_cells = sprintf('Young cells: Y = %3.3f (X) \\^%1.3f',coefs_young);
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