Feeds
提问
May you help me please to continue my syytem seconder order DE function?
function [dF1dx,dF2dx]=funode1(x,F) dF1dx=[F1(2);(Q/K1)*F1(1)-P/K1]; dF2dx=[F2(2);(Q/K2)*F2(1)-P/K2]; functio...
8 years 前 | 1 个回答 | 0
1
个回答提问
why i got this error?
Unexpected error function dFdx=funode(x,F) global Lamda global K1 global P dFdx=[F(2) ; -K1*P+F(1)*Lamda^2]; ...
8 years 前 | 1 个回答 | 0
1
个回答提问
I have a coupled second order DE; how to solve them with boundary conditions; How to get get F1 and F2
equation 1: d^2f1/dx^2-Q/K1*F1+P/K1=0 equation 2 d^2f2/dx^2-Q/K1*F2+P/K2=0 Boundary conditions F1(0)=0 F2(l)=P F1(l-u)=F2...
8 years 前 | 1 个回答 | 0
