Karolina

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How to begin with multiple graphs of 'y(x+1)=y(x)+0.02*randn;' from x=1? i.e. 10 graphs?
a=0; b=100; c=0; y=a+(b-a).*rand; for x=1:365 y(x+1)=y(x)+0.02*randn; if y(x+1)>100 y(x+1)=y(x) else i...

6 years 前 | 1 个回答 | 0

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