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this code of BAT algorithm is not working..function i wrote i last three lines..plz guide me
function [best,fmin,N_iter]=bat_algorithm(para) % Display help help bat_algorithm.m % Default parameters if n...
6 years 前 | 0 个回答 | 0
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In the code if i am changing the power of xdata from 0.1 to 0.9 i am getting same coefficient values 0.2000 10.00 10.00 of x1,x2 and x3. please suggest me what changes are required???
xdata =[10.^(-3) 10.^(-2) 10.^(-1) 1 10.^(1) 10.^(2)]; ydata=(0.5012./(xdata.^2+1.8*xdata+2.2 )); fun=@(x)sum(x(1)./((x(2).*xd...
6 years 前 | 0 个回答 | 0
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why a coefficient in optimization goes out of the bound???In my problem it is going out of lower bound.
In Interior search optimization for filters, value of one coefficient is equal to lower bound then if i am increasing the order ...
6 years 前 | 0 个回答 | 0
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Can i make 3d plot other than surf plot from these three values??? and how???
x=[0.2 0.2 0.5 0.5 0.8 0.9 ]; y=[0.8 0.9 0.8 0.9 0.9 0.5]; z=[0.9329 0.7530 0.9241 0.7058 1.0344 1.1110];
6 years 前 | 1 个回答 | 0
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I need all data points of magnitude and phase response of bode plot from figure.
I need all data points of magnitude and phase response of bode plot from figure.i need all coordinates of (mag,freq) and (phase,...
6 years 前 | 1 个回答 | 0
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This code is working but in every run i am getting different value of x(1),x(2) and x(3)..kindly solve this problem...its very urgent
xdata =[ 10.^(-5) 10.^(-4) 10.^(-3) 10.^(-2) 10.^(-1) 1] ; ydata=(0.2575./((xdata.^2)+(0.333.*xdata)+1)); parameterized...
6 years 前 | 1 个回答 | 0
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this code is giving same values of x irrespective of change in the power of xdata in fun???i am changing power 0.5 to 0.9 no change in output??
xdata =[10.^(-5) 10.^(-4) 10.^(-3) 10.^(-2) 10.^(-1) 1]; ydata=(0.2575./((xdata.^2)+(0.333.*xdata)+1)); fun=@(x)sum(x(1)...
6 years 前 | 1 个回答 | 0
1
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in every run i am getting different value of x..????
xdata =[ 1 2 3 4 5 6] ; ydata=(1./(xdata.^2+2*xdata+4)); FitnessFunction = @(x) sum((x(1)./(x(2).*xdata.^1.9+x(3).*xdata.^0.9+...
6 years 前 | 0 个回答 | 0
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GA is not working...Function i have written separately calling in main program but not worked??
xdata =[ 1 2 3 4 5 6] ; ydata=(1./(xdata.^2+2*xdata+4)); FitnessFunction = @simple_fitness; numberOfVariables = 3; x =ga(@g...
6 years 前 | 1 个回答 | 0
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i want to plot transfer function G ,how to do it???G=(((0.2274.*(4.7372.*(s).^(1+0.9)+1)))./((9.9944.*(s).^(1+0.9)))+0.3610.*(s).^(0.9)+1))));
G=(((0.2274.*(4.7372.*(s).^(1+0.9)+1)))./((9.9944.*(s).^(1+0.9)))+0.3610.*(s).^(0.9)+1))));
6 years 前 | 1 个回答 | 0
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i am getting error in last line. i want to find the value of x1,x2 and x3. please help me..
xdata =[10.^(-5) 10.^(-4) 10.^(-3) 10.^(-2) 10.^(-1) 1]; fun = @(x)x(1)./((x(2).*(xdata.^(1+0.9)))+x(3).*(xdata.^(0.9))+1);...
6 years 前 | 1 个回答 | 0
1
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From magnitude response of an analog low pass filter, how to get -3dB frequency in MATLAB
From magnitude response of an analog low pass filter, how to get -3dB frequency in MATLAB
7 years 前 | 0 个回答 | 0
0
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for α=0.2, β=0.5 >>> z= 27.5, for α=0.5, β=0.8 >>> z=17.0 , for α=0.2, β=0.8 >>>z=18.6,i want to get 3-D plot between α,β and Z without writting equation for Z.
for plotting surf ,kindly help me for my question.
7 years 前 | 1 个回答 | 0
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this is my code i am getting error with x = simulannealbnd(ObjectiveFunction,X0,ydata,lb,ub). can help me to resolve it
function y = parameterized_objective(x,xdata) y =x(1)./((x(2).*(xdata.^(1+0.9)))+x(3).*(xdata.^(0.9))+1); ydata=(0...
7 years 前 | 1 个回答 | 0